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Kíu bài 34

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Bài 34:
a) $x:\left(-\frac{3}{5}\right)^{10}=\left(-\frac{3}{5}\right)^{11}$ $x:\left(-\frac{3}{5}\right)^{10}=\left(-\frac{3}{5}\right)^{11}$
$x=\left(-\frac{3}{5}\right)^{11}\cdot \left(-\frac{3}{5}\right)^{10}$ $x=\left(-\frac{3}{5}\right)^{11}\cdot \left(-\frac{3}{5}\right)^{10}$
$x=\left(-\frac{3}{5}\right)^{21}$ $x=\left(-\frac{3}{5}\right)^{21}$
b) $x.\left(-\frac{4}{3}\right)^{20}=\left(-\frac{4}{3}\right)^{23}$ $x.\left(-\frac{4}{3}\right)^{20}=\left(-\frac{4}{3}\right)^{23}$
$x=\left(-\frac{4}{3}\right)^{23}:\left(-\frac{4}{3}\right)^{20}$ $x=\left(-\frac{4}{3}\right)^{23}:\left(-\frac{4}{3}\right)^{20}$
$x=\left(-\frac{4}{3}\right)^{3}$ $x=\left(-\frac{4}{3}\right)^{3}$
c) $\left(\frac{5}{7}\right)^{2022}:\left(x-1\right)=\left(\frac{5}{7}\right)^{2021}$ $\left(\frac{5}{7}\right)^{2022}:\left(x-1\right)=\left(\frac{5}{7}\right)^{2021}$
$\left(x-1\right)=\left(\frac{5}{7}\right)^{2022}:\left(\frac{5}{7}\right)^{2021}$ $\left(x-1\right)=\left(\frac{5}{7}\right)^{2022}:\left(\frac{5}{7}\right)^{2021}$
$x-1=\frac{5}{7}$ $x-1=\frac{5}{7}$
$x=\frac{5}{7}+1$ $x=\frac{5}{7}+1$
$x =\frac{12}{7}$ $x =\frac{12}{7}$
d) $\left(\frac{2}{5}\right)^9:\left(2x-3\right)=\left(\frac{8}{125}\right)^3$ $\left(\frac{2}{5}\right)^9:\left(2x-3\right)=\left(\frac{8}{125}\right)^3$
$\left(\frac{2}{5}\right)^9:\left(2x-3\right)=\left(\left(\frac{2}{5}\right)^3\right)^3$ $\left(\frac{2}{5}\right)^9:\left(2x-3\right)=\left(\left(\frac{2}{5}\right)^3\right)^3$
$\left(\frac{2}{5}\right)^9:\left(2x-3\right)= \left(\frac{2}{5}\right)^9$ $\left(\frac{2}{5}\right)^9:\left(2x-3\right)= \left(\frac{2}{5}\right)^9$
$\left(2x-3\right)=\left(\frac{2}{5}\right)^9: \left(\frac{2}{5}\right)^9$ $\left(2x-3\right)=\left(\frac{2}{5}\right)^9: \left(\frac{2}{5}\right)^9$
$2x-3 =1$
2x = 4
x = 2
0 Trả lời 15:01 16/07