Rút gọn:
\(\frac{10}{x+3}-\frac{8x-36}{x^2-9}\)
ĐK: x ≠ ±3
\(=\frac{10}{x+3}-\frac{8x\ -36}{\left(x+3\right)\left(x-3\right)}\)
\(=\frac{10\left(x-3\right)}{\left(x-3\right)\left(x+3\right)}-\frac{8x-36}{\left(x-3\right)\left(x+3\right)}\)
\(=\frac{10x-30-8x+36}{\left(x-3\right)\left(x+3\right)}\)
\(=\frac{2x+6}{\left(x-3\right)\left(x+3\right)}\)
\(=\frac{2\left(x+3\right)}{\left(x-3\right)\left(x+3\right)}\)
\(\frac{2}{\left(x-3\right)}\)
Đ/a là 2/x-3 nha
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