Tìm giá trị của x:

kq -2000

\(\frac{x+5}{1995}+1+\frac{x+4}{1996}+1+\frac{x+3}{1997}+1+\frac{x+2}{1998}+1+\frac{x+1}{1999}+1=0\)

\(\frac{x+5+1995}{1995}+\frac{x+4+1996}{1996}+\frac{x+3+1997}{1997}+\frac{x+2+1998}{1998}+\frac{x+1+1999}{1999}=0\)

\(\frac{x+2000}{1995}+\frac{x+2000}{1996}+\frac{x+2000}{1997}+\frac{x+2000}{1998}+\frac{x+2000}{1999}=0\)

\(\left(x+2000\right).\left(\frac{1}{1995}+\frac{1}{1996}+\frac{1}{1997}+\frac{1}{1998}+\frac{1}{1999}\right)=0\)

x+2000 = 0

=- 2000

Giúp mình với