Cách giải như nào

\(x^2-\sqrt{3}x-2-\sqrt{6}=0\)

\(\Leftrightarrow\)\(x^2+\sqrt{2}x-\left(\sqrt{2}+\sqrt{3}\right)x-2-\sqrt{6}=0\)

\(\Leftrightarrow\) \(x\left(x+\sqrt{2}\right)-\left(\sqrt{2}+\sqrt{3}\right)\left(x+\sqrt{2}\right)=0\)

\(\Leftrightarrow\)\(\left(x+\sqrt{2}\right)\left[x-\left(\sqrt{2}+\sqrt{3}\right)\right]=0\)

\(\Leftrightarrow\)\(x=-\sqrt{2}\) hoặc \(x=\sqrt{2}+\sqrt{3}\)

Hhhh